# Line slope calculator x+3y=6

**Straight line given by points A[0; 2] and B[3; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.3333x+2

**Canonical form of the line equation:**x+3y-6 = 0

**Parametric form of the line equation:**

x = 3t

y = -t+2 ; t ∈ R

**Slope:**m = -0.3333

**Slope angle of line: φ =**-18°26'6″ = -0.3218 rad

**X intercept:**x

_{0}= 6

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.8974

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(3; -1)

**Normal vector: n =**(1; 3)

**Midpoint of the segment AB: M =**[1.5; 1.5]

**Perpendicular Bisector equation:**3x-y-3 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (3; 1) ; |OB| = 3.1623**

**Scalar product OA .OB = 2**

**Angle ∠ AOB = 71°33'54″ = 1.249 rad**